Two stations A and B are 10 km apart in a straight track, and a train starts from A and
comes to rest at B. For three quarters of the distance, the train is uniformly accelerated and
for the remainder distance uniformly retarded. If it takes 15 minutes over the whole
journey, find its acceleration, retardation and the maximum speed it attains.
[S1 = 3/4 x 10,000 = 7500 m]
Also, vmax = 22.22 = a1t1
a1 = 22.22 / 675 = 0.0329 m/sec2. (Ans.)
and a2 = 3a1 = 3 x 0.0329 = 0.0987 m/sec2. (Ans.)
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