2. Water of m = 5 kg m , P = 1 MPa, H = 10,280 kJ. Determine temperature, total volume, total
internal energy and total entropy.
specific enthalpy h = H/m = 10,280kJ/5kg = 2056 kJ/kg
internal energy u = h - pv = 2056kJ/kg - (10^6 N/m^2)*(specific volume (m3/kg))
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