Answer to Question #183838 in Mechanical Engineering for Brian

Question #183838

Calculate a suitable diameter for a solid shaft to transmit power of 200kW when

running at 180rev/min if the maximum shear stress in the shaft must not exceed

85N/mm2


1
Expert's answer
2021-04-22T07:23:44-0400

Power "P = 200KW = 200,000 Nm"


RPM N = 180


"T = \\frac{P \\times 60}{2\\pi N} = \\frac{200000 \\times 60}{2\\pi 180} = 10.61 KNm"


Diameter of shaft "d = \\sqrt[3]{\\frac{16T}{\\pi\\times \\tau }} = \\sqrt[3]{\\frac{16\\times10.61\\times10^3}{\\pi\\times 85 }}=8.598mm"




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