A spring extends 3 inches when loaded vertically with 4 lbs. This weight was pulled further down by 3 inches an was released from rest. Determine the frequency of vibration in Hz
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15:08
"extension of spring = 3 inches = 0.0762 Meters"
"load = 4lbs = 1.814kgs" =18.14N
"k, spring constant = load\/ext"
"=18.4\/0.0762"
"=" 238.05N/m
weight required to pull the spring a further 3inches (0.0762m)
"=238.05*2(0.0762)"
"=36.27882N"
frequency F, = "1\/2\\pi *\\sqrt{K\/m}"
"=1\/2\\pi * \\sqrt{238.05\/36.27882}"
=4.02 Hz.
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