Question

A spring extends 3 inches when loaded vertically with 4 lbs. This weight was pulled further down by 3 inches an was released from rest. Determine the frequency of vibration in Hz

Answer 1

You

15:08

$extension of spring = 3 inches = 0.0762 Meters$

$load = 4lbs = 1.814kgs$ =18.14N

$k, spring constant = load/ext$

$=18.4/0.0762$

$=$ 238.05N/m

weight required to pull the spring a further 3inches (0.0762m)

$=238.05*2(0.0762)$

$=36.27882N$

frequency F, = $1/2\pi *\sqrt{K/m}$

$=1/2\pi * \sqrt{238.05/36.27882}$

=4.02 Hz.