Question #175245

An ideal compressor compresses 12kg/min of air isothermally from 99kPa and a specific volume of 0.81m^2/kg to a final pressure of 600kPa. Determine a)power(kw) required to drive the compressor b. change in entropy(kJ/K) c. heat transferred


1
Expert's answer
2021-04-01T01:10:28-0400

W=VdP=P1V1lnP2P1=mRT1lnP1P2W =-\int{VdP} = -P_1V_1\ln\dfrac{P_2}{P_1} = mRT_1\ln\dfrac{P_1}{P_2}


P1V1=RT1P_1V_1 = RT_1\\


T1=99×0.810.287=279.4KT_1 = \dfrac{99 × 0.81}{0.287} = 279.4K


W=12(0.287)(279.4)ln99600=17338kJ/minW =- 12( 0.287)(279.4)ln\dfrac{99}{600}= -17338kJ/min

=29kW= -29kW

Work is done on the system, because Work done is negative. There is a decrease in volume.


Heat transferred into the system is 17338J in one minute.


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