A circular metal plate with radius 0.22 m. Calculate the net torque about O given that F1 = 17.4 N, F2 = 7.2 N, F3 = 14 N, F4 = 5.4 N, θ1 = 58°, and θ2 = 38°.
F2⋅sin38°⋅0.22−F1⋅sin58°⋅0.22+F4⋅0+F3⋅0.22=F_2\cdot\sin38°\cdot0.22-F_1\cdot\sin58°\cdot0.22+F_4\cdot0+F_3\cdot0.22=F2⋅sin38°⋅0.22−F1⋅sin58°⋅0.22+F4⋅0+F3⋅0.22=
=7.2⋅sin38°⋅0.22−17.4⋅sin58°⋅0.22+=7.2\cdot\sin38°\cdot0.22-17.4\cdot\sin58°\cdot0.22+=7.2⋅sin38°⋅0.22−17.4⋅sin58°⋅0.22+
+5.4⋅0+14⋅0.22=0.81 (N⋅m)+5.4\cdot0+14\cdot0.22=0.81\ (N\cdot m)+5.4⋅0+14⋅0.22=0.81 (N⋅m) clockwise . Answer
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