Answer to Question #172816 in Mechanical Engineering for clar

Question #172816

A 45.3 - cm radius wheel is uniformly speeding up from 146 rev/min to 621 rev/min within 26.5 s. Find the tangential acceleration.


1
Expert's answer
2021-03-19T06:48:00-0400

Here revolution per min is given

"N_1=" 146 rev/min , "\\omega_1= \\frac{2\\pi N_1}{60}= \\frac{2\\times 3.14\\times 146}{60}=15.28 \\frac{rad}{s}"


"N_2= \\omega_2= \\frac{2\\pi N_2}{60}= \\frac{2\\times 3.14\\times 621}{60}=64.998 \\frac{rad}{s}"


t=26.5 s,

using first equation of rotation motion

"\\omega_2=\\omega_1+ \\alpha t"


"\\alpha=1.876 \\frac{rad}{s^2}"

"\\alpha" = angular acceleration


tangential acceleration,

"a= r \\alpha=0.85 \\frac{m}{s^2}"


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