Question #165479

Air with cv = 0.723 KJ/Kgm - °R is compressed in a piston-cylinder machine according to pV1.3 = c from an initial temperature of 17°C and pressure of 1 bar, to a final pressure of 5 bars. Determine the final temperature, the heat transferred and the work.


1
Expert's answer
2021-02-22T07:31:45-0500

cv = 0.723 KJ/Kg- °R,pV1.3 = c,T1T_1 =17°C and pressure of P1=1 bar, to a final pressure of ,P2=5 bars.

As per polytropic relation


P1P2=(T1T2)nn1\frac{P_1}{P_2}= (\frac{T_1}{T_2})^{\frac{n}{n-1}}

15=(290T2)1.31.31\frac{1}{5}= (\frac{290}{T_2})^{\frac{1.3}{1.3-1}}

T2=420.9KT_2=420.9 K

work done in polytropic process

W=nRΔTn1=1.3×8.314×130.899.3=4708.62JW=\frac{nR \Delta T }{n-1}= \frac{1.3 \times 8.314\times 130.899}{.3}=4708.62 J

Now heat transfer relation is

ΔQ=ΔU+ΔW\Delta Q= \Delta U+ \Delta W

ΔQ=nCvdT+W\Delta Q= nC_vdT+W

ΔQ=0.723×230.9+4708.62\Delta Q= 0.723\times 230.9 + 4708.62

Heat transfer is Q=4875.56 J


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26.02.21, 15:01

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23.02.21, 03:17

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