Air with cv = 0.723 KJ/Kgm - °R is compressed in a piston-cylinder machine according to pV1.3 = c from an initial temperature of 17°C and pressure of 1 bar, to a final pressure of 5 bars. Determine the final temperature, the heat transferred and the work.
cv = 0.723 KJ/Kgm - °R,pV1.3 = c,"T_1" =17°C and pressure of P1=1 bar, to a final pressure of ,P2=5 bars.
As per polytropic relation
"\\frac{P_1}{P_2}= (\\frac{T_1}{T_2})^{\\frac{n}{n-1}}"
"\\frac{1}{5}= (\\frac{290}{T_2})^{\\frac{1.3}{1.3-1}}"
"T_2=420.9 K"
work done in polytropic process
"W=\\frac{nR \\Delta T }{n-1}= \\frac{1.3 \\times 8.314\\times 130.899}{.3}=4708.62 J"
Now heat transfer relation is
"\\Delta Q= \\Delta U+ \\Delta W"
"\\Delta Q= nC_vdT+W"
"\\Delta Q= 0.723\\times 230.9 + 4708.62"
Heat transfer is Q=4875.56 J
Comments
Dear Rodel, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!
THANK YOU
Leave a comment