A nut needs to be tightened with a socket and a tommy bar to a torque of 50kg.m - if a force of 60kg is available, how long must the tommy bar be?
We know that torgue = force×length
T=F×L
Given torque T = 50 kg m, force F = 60 kg,
Subsstitute the values in the equation,
50= 60×L
L = 0.8334m.
The length of the tommy bar is L=0.8334m.
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