Find cv and cp for a certain fluid if the properties are related as follows: u = (196 + 0.718t) KJ/kgm and pv = [0.287(toc + 273)] where v is in m3/kgm and p is in KN/m2.
U = (196 + 0.718t) KJ/kg
Cv=dUdT=d(196+0.718t)dT\frac{dU}{dT}=\frac{d(196+0.718t)}{dT}dTdU=dTd(196+0.718t)
Cv=0.718kJkgKC_v=0.718 \frac{kJ}{kgK}Cv=0.718kgKkJ
PV=[0.287(toc + 273)]
Cp=Cv+P(δVdT)C_p=C_v+P(\frac{\delta V}{dT})Cp=Cv+P(dTδV)
Cp=0.718+.287=1.005KjkgKC_p=0.718+.287=1.005 \frac{Kj}{kgK}Cp=0.718+.287=1.005kgKKj
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