Question #150757

A 110 kg machine is mounted on an elastic foundation of stiffness 2 x106 When operating at 150 rad, the machine is subject to a harmonic force of magnitude 1500 N. The steady-state amplitude of the machine is measured as 1.9 mm. What is the damping ratio of the foundation?

Expert's answer

Natural frequency, ωn=km=2∗106110=134.84rads\omega_n=\sqrt{\frac{k}{m}}=\sqrt{\frac{2*10^6}{110}}=134.84\frac{rad}{s}

A=F0/k[1−(ωωn)2]2+[2ξωωn]2A=\frac{F_0/k}{\sqrt{[1-(\frac{\omega}{\omega_n})^2]^2+[\frac{2\xi\omega}{\omega_n}]^2}}

1.9∗10−3=1500/2∗106[1−(ωωn)2]2+[2ξωωn]21.9*10^{-3}=\frac{1500/2*10^6}{\sqrt{[1-(\frac{\omega}{\omega_n})^2]^2+[\frac{2\xi\omega}{\omega_n}]^2}}

[1−(ωωn)2]2+[2ξωωn]2=15002∗106∗1.9∗10−3=1538{[1-(\frac{\omega}{\omega_n})^2]^2+[\frac{2\xi\omega}{\omega_n}]^2}=\frac{1500}{2*10^6*1.9*10^{-3}}=\frac{15}{38}

[2.2248∗ξ]2=0.39473−0.05640[2.2248*\xi]^2=0.39473-0.05640

2.2248∗ξ=0.338342.2248*\xi=\sqrt{0.33834}

ξ=0.2614\xi=0.2614


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