Fb=2jNFb = 2 j NFb=2jN
Fa=Facosθ−Fbsinθ=3xcos30i−3xsin30j=2.59i−1.5jFa = Fa cos\theta - Fb sin\theta = 3 x cos30 i - 3 x sin30 j = 2.59 i - 1.5 jFa=Facosθ−Fbsinθ=3xcos30i−3xsin30j=2.59i−1.5j
Fnet=Fa+Fb=2j+2.59i−1.5j=2.59i+0.5jFnet = Fa + Fb = 2 j + 2.59 i - 1.5 j = 2.59 i + 0.5 jFnet=Fa+Fb=2j+2.59i−1.5j=2.59i+0.5j
Fnet=sqrt[2.59x2.59+0.5x0.5]=2.64NFnet = sqrt [ 2.59 x 2.59 + 0.5 x 0.5 ] = 2.64 NFnet=sqrt[2.59x2.59+0.5x0.5]=2.64N
Fnet=ma=2.64NFnet = ma = 2.64 NFnet=ma=2.64N
a=2.64/m=2.64/2=1.32m/s2a = 2.64/m = 2.64/2 = 1.32 m/s^2a=2.64/m=2.64/2=1.32m/s2
Hence,a=1.32m/s2Hence, a = 1.32 m/s^2Hence,a=1.32m/s2
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