Look head distance=15 m=ldl_dld , length of car =L=5 m, the angle between the vehicle's body line and look head line is,α=60o\alpha=60^oα=60o
Now for steering angle we know that
δ=tan−1(2Lsinαld)=tan−1(2×5×sin6015)=30o\delta=tan^{-1}(\frac{2Lsin \alpha}{l_d})=tan^{-1}(\frac{2\times 5\times sin 60}{15})=30^oδ=tan−1(ld2Lsinα)=tan−1(152×5×sin60)=30o
So, here steering angle is 30o
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