For beam A we have dimension as L"_A=" 2.5 inch, B"_A=1.5 , H_A=0.5 inch"
for flexural modulus we know that
"E_F= \\frac{L^3 m}{bd^3}= \\frac{2.5^3 \\times m}{1.5\\times 0.5^3}=41.67 m"
Similary, for the beam B which has dimension given as "1.5\\times 1.5\\times 0.75"
"E_F= \\frac{L^3 m}{bd^3}= \\frac{1.5^3 \\times m}{1.5\\times 0.75^3}= 4 m"
So here we are getting different flexural modulus for beam A and beam B
The flexural modulus of A is more than that of B
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