The relation between pressure(P) and volume (V) of a closed system is given as
P×V=3=constant
P=V3 ---------------------------------------(1)
P1×V1=P2×V2
when P=1.5 bar=1.5×105Pa => V=1.5×1053=2×10−5 m3
when P=7.5 bar=1.5×105Pa => V=7.5×1053=0.4×10−5m3 m3
The work done during the process is given by
W=∫V1V2PdV=∫2×10−50.5×10−5V3]dV=3×ln(20.4)=−3×1.6J=−4.828J
Negative sign indicates work done on the system.
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