Answer to Question #136165 in Mechanical Engineering for dilan

Question

A vessel with a volume of 0.03 m3 contains saturated vapor at a pressure of 17 bar. Determine the mass of the vapor and having found the mass value, determine the enthalpy value
? and also explain why X (quality) = 1

Answer 1

As per the given data:

Volume of saturated steam (V)=0.03 m³.

At pressure (P)=17 bar=1.7 MPa

From steam table,

The specific volume (Vg)=0.11667 m³/kg.

The specific Entalpy (h_g)=2794.5kJ/kg

Therefore,

Mass of steam(M)= $\frac {Volume of steam (V)}{Specific volume(Vg)}$

$M= \frac {0.03}{0.1166}=0.257 kg$

Therefore , Enthalpy (H)=m h_g=0.257x2794.5 kJ=718.75 KJ

Since steam is saturated, it doesn't contain any liquid phase, therefore it's dryness is 100% and it's quality (x)=1.