Let the radius be r
let us assume C is at the edge
so distance from center=rft
B will then be = (r−122)ft
angular velocity will be same hence
RbVb=RcVc
(r−61)700=r880
(r−61)r=1.257
r=1.257r−0.2095
0.257r=0.2095
r=0.815ft
Hence C is at 0.815 ft and B is at 0.648 ft
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