Answer to Question #131937 in Mechanical Engineering for Wajahat ul ishaq

Question

A rod 2m long and of diameter 30mm is subjected to an axial pull of 30kN. If the young’s
modulus of the material of the rod is 2x105 N/mm2
, determine
a) stress
b) strain and
c) Elongation

Answer 1

the cross sectional area,A = (22/7d²)/4= (22/7*30²)/4 = 707.143mm²

a)stress = load/area = 30000/707.143 = 42.424N/mm²

b)strain = stress/young's modulus = 42.424/200000= 0.00021212

c)elongation = load*length/area* young's modulus = 30000*2000/707.143*200000 = 0.424mm