Doubling time is given as ,
Td= 6.5 , We know that
Dilution rate= "\\frac{F}{V}" , here F=Volumetric flow rate, V= Volume
and under case of limiting substrate
"\\mu_{max}= \\frac{0.693}{T_d}"
And in case of limiting substrate, "\\mu_{max}=D" here, D= Dilution rate
so,
"D=\\frac{0.693}{T_d}"
"D=\\frac{0.693}{6.5}"
D= 0.1066 "hr^{-1}" , This is dilution rate
Comments
Dear Kamanam Sai Kumar, Questions in this section are answered for free. We can't fulfill them all and there is no guarantee of answering certain question but we are doing our best. And if answer is published it means it was attentively checked by experts. You can try it yourself by publishing your question. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.
Please solve this problem I tried to do but not coming now you guys are sending empty with not anwered
Leave a comment