Mass of saturated water(m)= 2kg
Saturation pressure (p)=125kPa=0.125 MPa
From steam table , at p=0.125MPa, the specific volume of saturated water(v) = 0.001048 M3/kg
And specific volume of saturated steam(vg)=1.3768m3/kg
Therefore, volume of saturated water(Vf)=m.vf=2x0.001048=0 .00209 m3.
And the volume of saturated steam (Vg)=m.vg=2x1.3768=2.7567 m3
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