Answer to Question #127818 in Mechanical Engineering for Arthur

Question #127818

A uniaxial steel bar is initially 250mm in length with a square cross-section of 50mm x 50mm. The modulus of elasticity is 200 GPa and a poisson's ratio is 0.32 Determine the change in dimensions of the bar when carrying tensile load of 600kn.


1
Expert's answer
2020-07-29T06:45:19-0400

Steel bar:

Length(L)=250mm, bredth(B)=50mm and Height(H )=50mm

Modulus of elasticity(E)=200GPa=2x105 N/mm2

Poissons ratio( μ)=0.32

Tensile Load(P)= 600000 N

"Change in length(\\Delta L)=\\frac{PL}{AE}"

"\\Delta L=\\frac{600000\\times 250}{50\\times 50\\times 200000}=0.3mm"

Strain along length(eL)=(change in length)/(Length)=0.3/250=1.2x10-3

Change height(ΔH)=change in bredth(ΔB)=-(μxeL)xH=-0.0192mm(-ve sign indicates reduction in dimension)







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