Here, we have given density of air as 1.225 "\\frac{kg}{m^3}" , Torsional stifness= 10 Nm/rad
Here figure attached to this question is below
So here ,
Net torque= Force*perpendicular distance
Torsional stiffness"\\times angle=\\rho A v^2 \\times side"
"10\\times 10 \\times \\frac{\\pi}{180}=1.225 \\times 1\\times v^2 \\times0.5"
v=1.687 m/s is the velocity of air
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