Question #122318

using the equipartition of energy concept estimate the ideal gas Cp(not Cv) in units KB for the low temperature regime where no vibrational modes are activated(if you calculate Cp=42KB, enter 42 as your answer )

Expert's answer

As per equipartition theorem,

The energy of a thermodynamic system in equilibrium is partitioned equally among its degrees of freedom and molar heat capcity is given as

Cv=d2R,C_v=\frac{d}{2}R,

and we know that Cp=Cv+RC_p=C_v+R

Cp=d2R+RC_p=\frac{d}{2}R+R

where d is the degree of freedom, for ideal gas d=3

Now,

Cv=32R,Cp=32R+R=52RC_v=\frac{3}{2}R, C_p=\frac{3}{2}R+R=\frac{5}{2}R , we know that

R=NKB,

R=6.022×1023KBR=6.022\times 10 ^{23}K_B


CP=15×1023KBC_P=15\times10^{23}K_B

so u need to write 15


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