Question #117232

an lvdt is used to measure the axial deformation of the simple bar of fig. 10.3. the uncertainty in this measurement is ±0.025 mm. a steel bar is to be used to measure a force of 1100 n with an uncertainty of 1 percent. determine a suitable diameter and length of rod for this measurement, assum- ing the rod dimensions will be known exactly

Expert's answer

F=AELyF=\frac{AE}{L}y E=28.3∗106psi=1.95∗1011 N/m2E=28.3\ast{10}^6psi=1.95\ast{10}^{11}\ N/m^2

∂F∂y=AEL\frac{\partial F}{\partial y}=\frac{AE}{L} and WFF=∂F∂yWyF=Wyy\frac{W_F}{F}=\frac{\partial F}{\partial y}\frac{W_y}{F}=\frac{W_y}{y}

y=100∗0.025mm=2.5mmy=100*0.025 mm = 2.5 mm

AL=FEy=11001.95∗1011∗2.5∗103=2.255∗10−6\frac{A}{L}=\frac{F}{Ey}=\frac{1100}{1.95\ast{10}^{11}\ast2.5\ast{10}^3}=2.255\ast{10}^{-6}

ConsideringL=0.1m=>A=π.d2/4=(0.1)(2.255∗10−6)Considering L=0.1 m => A=\pi . d^2/4 = (0.1)(2.255*10^{-6})

d=5.36∗10−4m=0.536mmd=5.36*10^{-4} m = 0.536 mm



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