Here, T4=250C=25+273=298KT_4= 25 ^0C= 25+273=298 KT4=250C=25+273=298K , T3=10+273=283T_3=10+273= 283T3=10+273=283
(2) Practical cop=50×19.867100=9.93= \frac{50 \times 19.867 }{100}=9.93=10050×19.867=9.93
ηl=π4d2l\eta_l= \frac{ \pi}{4} d^2lηl=4πd2l
0.85=π4d2×1.5d0.85= \frac{ \pi}{4} d^2\times1.5 d0.85=4πd2×1.5d
d3=2.267d^3=2.267d3=2.267
d=1.31 m
and length= 1.965 m
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