A house initially at a temperature 310k during a hot summer day must be cooled to a temperature 294k while the ambient temperature is 310k. Obtain an expression for the minimum workdone required and determine the minimum work also required to cool a room containing the total area of 200 meter square with equivalent mass of 50 kilogram meter square of the living room.
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Expert's answer
2020-04-28T12:26:28-0400
Total mass of air required= "200\\times 50=10000"
at ambient condition temperature will be constant so internal energy will be constant and thus from first law of thermodynamics
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