(A) Diameter of large pipe cross section=250 mm
and the flow rate through that pipe= 87 l/sec= "87 \\times 10^{-3} \\frac{m^3}{s}"
Q=av, Q= flow rate
"Q= a_1v_1=87 \\times 10^{-3} \\frac{m^3}{s}"
"v_1=\\frac{87 \\times 10^{-3} \\frac{m^3}{s}}{a_1}"
As per equation of continuity flow rate remain same
so, as per the question pipe divide in two equal diameter so velocity in both pipe remain same and thus we can say that,
"a_1v_1= 2\\times a_2\\times v_2"
"a_1\\times \\frac{87 \\times 10^{-3} \\frac{m^3}{s}}{a_1}= 2\\times (\\frac{\\pi}{4})\\times (0.01)^2 \\times v_2"
"v_2=" 5.54 m/s
(B) As per the conservation of momentum momentum remain conserved and due this principle the fluid exert pressure force in two direction i.e in vertical direction and in horizontal direction
and nozzle is a device which converts the energy from a fluid into velocity of the spray droplets.
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