Volume of rigid tank is = 0.5 m3, Using the table for refrigerant R-134a we can draw the following property at 200 KPA and At 0.4 quality
vf=0.0007535 ,vg=.1234
v1=vf+xvg
v1=0.0007535+0.4×.1234
v1=0.05011 , similarly from data table we will get the value of u1=107.19
Q=m(u2−u1)=2708Kj
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Thank you for these solutions.
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wow what an "expert" answer. very detailed i see. thanks for nothing