Answer to Question #110601 in Mechanical Engineering for Dilkhush meena

Question

An object of 30 kg is moved with a velocity of 2 m/s on a horizontal smooth surface. What is the velocity of the block for 4 seconds if force of 40 N is applied on it in the direction of force?

Answer 1

mass of body= 30 Kg, initial velocity of body= 2 m/s and Force acting on it=40 N for 4 sec

F=ma

40=30a

a=1.33 $\frac{m}{s^2}$

Now after 4 sec velocity become,

v=u+at

v= 2+1.33$\times4=7.32 m/s$

So, velocity after 4 sec becomes 7.32 m/s