Question #110442
Calculate Reynolds number, if a fluid having viscosity of 0.4 Ns/m2 and relative density of 900 kg/m3 through a pipe of 20mm with a velocity of 2.5 m.
1
Expert's answer
2020-04-19T07:40:03-0400

Reynold number is used to determine the flow of fluid which is laminar or turbulent


Re=ρvdμR_e= \frac{\rho vd}{\mu} , here ρ=density\rho= density of fluid=900kgm3900 \frac{kg}{m^3} , v= velocity of the fluid =2.5 m/s


d= diameter of pipe=20 mm= 0.02m, μ\mu = coefficient of viscosity= 0.4 Nsm2\frac {Ns}{m^2}


Re=ρvdμR_e= \frac{\rho vd}{\mu}


Re=900×2.5×0.020.4R_e= \frac{900\times 2.5\times 0.02}{0.4}


Re=R_e= 112.5

So, The Reynold number for this fluid flow is =112.5




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