Question #108895
a car accelerates with a constant acceleration of 1.2ms^-1 along a long straight road.how long does it take the car to accelerate from 100kph to 110kph,and how far does it travel while doing so?
1
Expert's answer
2020-04-10T13:41:05-0400

Given:-

Acceleration(a) =1.2 m/s2

Car speed(accelerate from).

u=100kph=72.78m/s.v=110kph=30.56m/s.u=100 kph = 72.78 m/s.\\[5pt] v = 110 kph = 30.56 m/s.


Now,

From Kinetic equation.

v=u+att=vuat=30..56m/s27.78m/s1.2m/s2t=2.315sec.v=u+at\\[5pt] \\t=\frac{v-u}{a}\\[8pt] \\t=\frac{30..56 m/s-27.78 m/s}{1.2 m/s^{2}}\\[5pt] t=2.315 sec.

So,

The time taken by car to travel from speed .

t=2.315sec.\\t=2.315 sec.


Now,

Again , use following kinetic equation .

v2u2=2ass=v2u22as=(30.56m/s)2(27.78m/s)22×1.2m/s2s=67.56mv^{2}-u^{2}=2as\\[5pt] s=\frac{v^{2}-u^{2}}{2a}\\[5pt] s=\frac{(30.56m/s)^{2}-(27.78m/s)^{2}}{2\times 1.2m/s^{2}}\\[5pt] s=67.56 m

So,

The distance traveled by the the car is.

s=67.56ms=67.56 m






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