Given:-
Acceleration(a) =1.2 m/s2
Car speed(accelerate from).
u=100kph=72.78m/s.v=110kph=30.56m/s.
Now,
From Kinetic equation.
v=u+att=av−ut=1.2m/s230..56m/s−27.78m/st=2.315sec.
So,
The time taken by car to travel from speed .
t=2.315sec.
Now,
Again , use following kinetic equation .
v2−u2=2ass=2av2−u2s=2×1.2m/s2(30.56m/s)2−(27.78m/s)2s=67.56m
So,
The distance traveled by the the car is.
s=67.56m
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