A series RL circuit consists of resistor with a resistance of 50.0 Ω and an inductor with an
inductance of 200 µH. The instantaneous voltage across the resistor (VR) is given as
VR = ( 10.5 V) cos (2000π t)
a) Derive an equation for the instantaneous current that flows in the circuit. (2 marks)
b) Calculate the reactance of the circuit. (1 mark)
c) Derive an equation for the instantaneous voltage across the inductor, VL. (3 marks)
d) Sketch a phasor diagram of the circuit. (1 mark)
e) Determine the equation for the instantaneous voltage of the ac source, Vs. (3 marks)
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