Question #285299

Two resistor RA = 1.95ohms, and RB = 0.05 ohm are connected in parallel and take a total current of 50 amp. What is the current through each resistor.


1
Expert's answer
2022-01-07T14:33:01-0500

Given:

RA=1.95ΩR_A=1.95\:\Omega

RB=0.05ΩR_B=0.05\:\Omega

I=50AI=50\:\rm A


The parallel conection equations give

I=IA+IB,IARA=IBRB.I=I_A+I_B,\\ I_AR_A=I_BR_B.


In our case


50=IA+IB,1.95IA=0.05IB.50=I_A+I_B,\\ 1.95I_A=0.05I_B.

We get

IB=39IAI_B=39I_A

50=40IA50=40I_A

Finally

IA=50/40=1.25AI_A=50/40=1.25\:\rm A

IB=39IA=391.25A=48.75AI_B=39I_A=39*1.25\:\rm A=48.75\: A


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