Answer to Question #285299 in Electrical Engineering for Question011

Question

Two resistor RA = 1.95ohms, and RB = 0.05 ohm are connected in parallel and take a total current of 50 amp. What is the current through each resistor.

Answer 1

Given:

$R_A=1.95\:\Omega$

$R_B=0.05\:\Omega$

$I=50\:\rm A$

The parallel conection equations give

$$I=I_A+I_B,\\ I_AR_A=I_BR_B.$$

In our case

$$50=I_A+I_B,\\ 1.95I_A=0.05I_B.$$

We get

$$I_B=39I_A$$

$$50=40I_A$$

Finally

$$I_A=50/40=1.25\:\rm A$$

$$I_B=39I_A=39*1.25\:\rm A=48.75\: A$$