Answer to Question #230920 in Civil and Environmental Engineering for syra

Question #230920
Find the equation of the family of curve having the given slope, and the equation of the family which passes through the given point.

m= 2x⁴/x; (0,5)

Note: the slope m = dy/dx
1
Expert's answer
2021-08-31T23:56:04-0400

Considering the following equation of the slope

dydx=2x4x=2x3\frac{dy}{dx}= \frac{2x^4}{x}= 2x^3

Separating the variables

dy=2x3dxdy=2x3dxy=2x44+Cy=x42+Cdy = 2x^3 dx\\ \int dy = \int 2x^3 dx\\ y= \frac{2x^4}{4}+C\\ y= \frac{x^4}{2}+C\\

Finding the value of C

y=x42+C5=042+CC=5y= \frac{x^4}{2}+C\\ 5= \frac{0^4}{2}+C\\ C=5

The equation of the curve is given as

y=x42+5y= \frac{x^4}{2}+5\\


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