Question #196910

Determine the total thrust on the back of a smooth vertical wall, 8m high, which is supporting granular backfill with bulk unit weight 18kN/m3 and angle of friction of 33 degrees. The soil surface is horizontal and the water table lies 2.2m below ground level. Assume the saturated unit weight of backfill is 22kN/m3 below water table. 



1
Expert's answer
2021-05-24T18:59:02-0400



ka=1sin331+sin33=0.2948k_a= \frac{1-sin 33}{1+sin 33}= 0.2948


vertical pressure= ka.γHk_a. \gamma H


  1. 0.2948 ×18×2.2=11.6741KN/m2\times 18 \times 2.2 = 11.6741 KN/m^2


0.2948×22×5.8=37.616KN/m20.2948 \times 22 \times 5.8 = 37.616 KN/m^2


pressure due to γw.H2=9.81×5.8=56.898KN/m2\gamma_w . H_2= 9.81 \times 5.8 = 56.898 KN/m^2


Total vertical thrust = (12×11.6741×2.2)+(11.6741×5.8)+(12×37.616×5.8)+(12×56.898×5.8)( \frac{1}{2} \times 11.6741 \times 2.2 ) + (11.6741\times 5.8) +(\frac{1}{2} \times 37.616\times 5.8) +(\frac{1}{2} \times 56.898\times 5.8)


Pa=12.84151+67.707978+109.0864+165.004=354KNP_a= 12.84151 +67.707978 +109.0864 +165.004= 354 KN


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS