a test of a driver's perception reaction time is being conducted on a special testing track with wet pavement and a driving speed of 50 kph. when the driver is sober, a stop can be made just in time to avoid hitting an object that is visible 40 m. ahead. after a few drinks of san miguel beer, under exactly the same condition, the driver fails to stop in time and strikes the object at a speed of 30 kph. determine the driver's perception-reaction time after he was drinking. assume coefficient of friction is 0.60.
The driver's perception-reaction time is:
"t=t_1-t_2" ,
where "t_1" - the time from the moment, when the driver presses the brake, to the moment, when the car stops;
"t_2" - the time from the moment, when the driver presses the brake, to the moment, when the car strikes the object at a speed of 30 kmph.
First, find "t_1". The car speed depends on time as follows:
"v=v_0+at" ,
where "v_0" - the initial speed;
"a" - the acceleration.
In the first case "v=0", so
"t_1=-\\frac{v_0}{a}" .
The acceleration can be found from the Newton's second law:
"ma=-\\mu mg,"
"a=-\\mu g."
Henсe, assuming that 50 kmph is 13,89 mps,
"t_1=\\frac{v_0}{\\mu g}=\\frac{13.89}{0.6\\cdot 9.81}=2.36\\space s."
Then, find "t_2". In the second case "v=30\\space kmph" or "8.33\\space mps" so
"t_2=\\frac{v_0-v}{\\mu g}=\\frac{13.89-8.33}{0.6\\cdot 9.81}=0.95\\space s."
"t=t_1-t_2=2.36-0.95=1.41\\space s."
Answer: The driver's perception-reaction time is 1.41 seconds.
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