Answer to Question #155140 in Civil and Environmental Engineering for lameck omenyi

Question #155140

Design a pipe line for village considering following figure. It is

stipulated that one half of the daily supply of 150 litres per capita

per day should be delivered with in eight hours. Take C=45

a)      What must be the size of the pipe to furnish the supply,

if the head available is 12 meters?

b)     If the velocity in this pipe (friction= 0.002 is

ristricted to 1.5 m/sec, find the head loss?



1
Expert's answer
2021-01-19T05:19:48-0500

a) According to Hazen-Williams equation

Head loss s=10.67Q1.85C1.85d4.87s=\frac{10.67 Q^{1.85}} {C^{1.85}d^{4.87}}

where Q=Q= flow rate in m3/sm^3/s


S=S= head loss mm

d=d= diameter mm


half of 150 litres is to be suplied for atlest 8 hours in each day.

therefore

Q=Q= 0.075 m3/sm^3/s


S=S= 10.67×0.0751.85451.85×d4.87\frac{10.67\times 0.075^{1.85}} {45^{1.85}\times d^{4.87}}


d=d= 10.67×0.0751.85451.85×124.87\sqrt[4.87]{\frac{10.67\times 0.075^{1.85}} {45^{1.85}\times 12^{}}}

d=0.08593md= 0.08593 m or d=86mmd= 86 mm


b) Assume that the total length of the pipe used to supply water is about 120 m with the provisions:

velocity=1.5 m/sm/s and a coefficient of friction = 0.002


Darcy's formula for head loss deu to friction states the following

hϝh\digamma = 4fLv22gd\frac{4fLv^{2}} {2gd}

where hϝh\digamma = head loss due to friction

ff = coefficient of friction

LL = lenght of pipe mm

vv = velocity of water flowing

gg = gravitational acceleration usually 9.81m/s2m/s^2

dd = diameter of pipe in mm


hϝh\digamma =4×0.002×120×1.522×9.81 0.086=1.28m\frac{4\times 0.002\times 120\times 1.5^{2}} {2\times 9.81\ 0.086} = 1.28 m




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment