Question #156670

Suppose that the production function is given by = 2x0.5. The price of is $3 and the price of is $4. Derive the corresponding VMP and AVP functions. What is MFC? Solve for the profit-maximizing level for input use x.


1
Expert's answer
2021-01-20T14:59:56-0500

Let Px=$3,Py=$4.P_x=\$3, P_y=\$4.

Then, the total value of the product (TVP) can be written as follows:


TVP=Pyy.TVP=P_y\cdot y.


The VMP can be found as follows:


VMP=dTVPdx=Pyddx(2x0.5)=Py1x.VMP=\dfrac{dTVP}{dx}=P_y\dfrac{d}{dx}(2x^{0.5})=P_y\cdot\dfrac{1}{\sqrt{x}}.


The total factor cost (TFC) can be written as follows:


TFC=Pxx.TFC=P_x\cdot x.

The profit function can be written as:


Π=TVPTFC=PyyPxx.\Pi=TVP-TFC=P_y\cdot y-P_x\cdot x.

By the definition, the marginal factor cost (MFC) equals:


MFC=dTFCdx=ddx(Pxx)=Px=$3.MFC=\dfrac{dTFC}{dx}=\dfrac{d}{dx}(P_x\cdot x)=P_x=\$3.

Average value product (AVP) can be written as:


AVP=Py2x0.51x.AVP=P_y\cdot2x^{0.5}\cdot\dfrac{1}{x}.

The profit-maximizing level:


ddxΠ=0,\dfrac{d}{dx}\Pi=0,PydydxPx=0,P_y\dfrac{dy}{dx}-P_x=0,Pyddx(2x0.5)Px=0,P_y\dfrac{d}{dx}(2x^{0.5})-P_x=0,Py1xPx=0,P_y\cdot\dfrac{1}{\sqrt{x}}-P_x=0,x=(PyPx)2=($4$3)2=1.77x=(\dfrac{P_y}{P_x})^2=(\dfrac{\$4}{\$3})^2=1.77


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