7. Suppose that cost function is of a firm is given by C=Q 3 -4Q 2 +14Q+60. Then , determine
a. Fixed Cost function and AFC at Q=2
b. TVC function and AVC at Q=2
c. MC function and MC at Q=2
d. Minimum average cost
8. Suppose Q gives the production function Q=150KL and the price of labor and capital is 2.5 and 6 birr respectively. If the total outlays of the firm is 3000 Birr. Determine the level of employment of both inputs that maximizes output.
Solution:
7.). a.). Fixed Cost Function and AFC at Q = 2
C = Q3 – 4Q2 + 14Q + 60
Fixed Cost Function = 60
Average Fixed Cost (AFC) = "\\frac{TFC}{Q}" = "\\frac{60}{2}" = 30
b.). TVC function and AVC at Q = 2:
TVC function = Q3 – 4Q2 + 14Q
AVC = "\\frac{TVC}{Q}" = Q3 – 4Q2 + 14Q"\\div" Q = Q2 – 4Q + 14 = 22 – 4(2) + 14 = 4 – 8 + 14 = 10
AVC = 10
c.). MC function and MC at Q=2:
MC function = "\\frac{\\partial TC} {\\partial Q}" = 3Q2 – 8Q + 14
MC = 3Q2 – 8Q + 14 = 3(22) – 8(2) + 14 = 12 – 16 + 14 = 10
MC = 10
d.). Minimum average cost:
Derive average cost:
Average cost = Q3 – 4Q2 + 14Q + "\\frac{60}{Q}" = Q2 – 4Q + 14 + "\\frac{60}{Q}"
AC = Q2 – 4Q + 14 + "\\frac{60}{Q}"
"\\frac{\\partial AC} {\\partial Q}" = 2Q – 4 – "\\frac{60}{Q^{2} }"
2Q – 4 – "\\frac{60}{Q^{2} }" = 0
Q = 3.94
Minimum Average Cost = 3.94
8.). Derive MPL and MPK
MPL = "\\frac{\\partial Q} {\\partial L}" = 150K
MPK = "\\frac{\\partial Q} {\\partial K}" = 150L
Maximization is where: "\\frac{MP_{L} } {MP_{K} }" = "\\frac{w}{r}"
w = 2.5
r = 6
"\\frac{150K}{150L} = \\frac{2.5}{6}"
K = 2.39L
Q = 150KL
3,000 = 150 (2.39L) (L)
3000 = 358.5L2
L = 2.89
K = 2.39L = 2.39 (2.89) = 6.9
K = 6.9
The level of employment of both inputs that maximize output (L, K) = 2.89, 6.9
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