Answer to Question #187141 in Microeconomics for salman

Question #187141

Suppose that the production function of the firm is:

Q = 100L1/2.K1/2

 K= 100, P = $1, w =$50. and r = $40. Determine the quantity of labor that the firm should hire in order to maximize the profits. What is the maximum profit of this firm?





1
Expert's answer
2021-05-03T10:47:28-0400

Given:

production function

"Q=100L^{\\frac{1}{2}}K^{\\frac{1}{2}}"

K=100

P=$1

W=$50

r=$40

To find the quantity of labor that maximizes the profit, let us equate the value of the marginal product of labor (MPL) and the wage.

Marginal product of labor(VMPL) "=\\frac{\\delta Q}{\\delta L}"

"MPL=100\\times \\frac{1}{2}\\times L^{\\frac{-1}{2}}\\times K^{\\frac{1}{2}}"

Substitute value of K=100

"MPL=\\frac{500}{L^{\\frac{1}{2}}}"


To find the value of MPL, multiply the price of output (P) with MPL.

"VMPL=1\\times\\frac{500}{L^{\\frac{1}{2}}}"

At equilibrium

VMPL=W

"\\frac{500}{L^{\\frac{1}{2}}}=50"


"L^{\\frac{1}{2}}=\\frac{500}{50}"


"L^{\\frac{1}{2}}=10"


"L=10^2=100"

The firm will hire 100 labors to maximize profit.

 

Profit: profit refers to the difference between the total revenue and total cost.

Total revenue:


Substitute the value of L=100 and K=100 in the production function

"Q=100\\times(100)^{\\frac{1}{2}}\\times(100)^{\\frac{1}{2}}"

"Q=100\\times10\\times10"

"Q=10,000"

Total Revenue "=Q\\times P=10000\\times 1=\\$10,000"

Now,

Total cost "=wL+rK=(50\\times100)+(40\\times100)=\\$9,000"


Profit=Total Revenue-Total Cost

"Profit=10,000-9,000=\\$1,000"


The maximum profit of the firm at L=100 is $1000.


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