Suppose that the production function of the firm is:
Q = 100L1/2.K1/2
 K= 100, P = $1, w =$50. and r = $40. Determine the quantity of labor that the firm should hire in order to maximize the profits. What is the maximum profit of this firm?
Given:
production function
"Q=100L^{\\frac{1}{2}}K^{\\frac{1}{2}}"
K=100
P=$1
W=$50
r=$40
To find the quantity of labor that maximizes the profit, let us equate the value of the marginal product of labor (MPL) and the wage.
Marginal product of labor(VMPL) "=\\frac{\\delta Q}{\\delta L}"
"MPL=100\\times \\frac{1}{2}\\times L^{\\frac{-1}{2}}\\times K^{\\frac{1}{2}}"
Substitute value of K=100
"MPL=\\frac{500}{L^{\\frac{1}{2}}}"
To find the value of MPL, multiply the price of output (P) with MPL.
"VMPL=1\\times\\frac{500}{L^{\\frac{1}{2}}}"
At equilibrium
VMPL=W
"\\frac{500}{L^{\\frac{1}{2}}}=50"
"L^{\\frac{1}{2}}=\\frac{500}{50}"
"L^{\\frac{1}{2}}=10"
"L=10^2=100"
The firm will hire 100 labors to maximize profit.
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Profit: profit refers to the difference between the total revenue and total cost.
Total revenue:
Substitute the value of L=100 and K=100 in the production function
"Q=100\\times(100)^{\\frac{1}{2}}\\times(100)^{\\frac{1}{2}}"
"Q=100\\times10\\times10"
"Q=10,000"
Total Revenue "=Q\\times P=10000\\times 1=\\$10,000"
Now,
Total cost "=wL+rK=(50\\times100)+(40\\times100)=\\$9,000"
Profit=Total Revenue-Total Cost
"Profit=10,000-9,000=\\$1,000"
The maximum profit of the firm at L=100 is $1000.
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