Question #210662

1a)The following distribution represents the number of minutes spent by a herd of cows in grazing

Minutes/week 0-99 100-199 200-299 300-399 400-499 500-599 600 & more

Number of cows 21 26 59 72 52 26 8

Determine the median.

b)If coveriance between X and Y is 18.8 and the variance of X and Y are 22.4 and 26.8 respectively. Find the coefficient of correlation between them.




1
Expert's answer
2021-06-29T08:15:58-0400

Solution:

1.a). The median value for the number of cows:

Number of cows = 21 26 59 72 52 26 8


First sort the numbers in ascending order:

Number of cows sorted = 8 21 26 26 52 59 72

Median = (n+1)2\frac{(n + 1)}{2}

Where n = the number of values in the data set.


Median = (7+1)2=82=4\frac{(7 + 1)}{2} = \frac{8}{2} = 4

The 4th value in the data set will be the median value. The 4th value in the data set is 26

 

Median value = 26

 

b.). Coefficient correlation (X, Y):


rX,Y=SXY(SXSY)r_{X,Y} = \frac{S_{XY} }{(S_{X}S_{Y}) }


Where:

·        rXY = Correlation between X and Y

·        SXY = Covariance between X and Y

·        SX = Standard deviation of X

·        SY = Standard deviation of Y

Covariance between X and Y (SXY) = 18.8

Standard deviation = Square root of variance

Variance of X = 22.4

Variance of Y = 26.8

Standard deviation of X = 22.4=4.7329\sqrt{22.4} = 4.7329


Standard deviation of Y = 26.8=5.1769\sqrt{26.8} = 5.1769


Coefficient correlation (r,XY) = 18.8(4.7329)(5.1769)=18.824.5014=0.7673\frac{18.8 }{(4.7329)(5.1769) } = \frac{18.8 }{24.5014 } = 0.7673


Coefficient of correlation between X and Y = 0.7673



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