Answer to Question #87859 in Chemistry for Lily

Question

Determine the new volume of a gas at that occpies an original volume of 55 L at 750mmHg and 25 degrees celsius if the pressure is changed to 1.03 atm and the temperature to 30 degrees celsius.

Answer 1

According to the ideal gas equation:

P₁V1/T₁ = P₂V₂/T₂,

where P₁, V₁, T₂ - initial pressure, volume and temperature, P₂, V₂, T₂ - pressure, volume and temperature

As a result:

V₂ = P₁V₁T₂ / T₁P₂.

Here,

P₁ = 750 mmHg = 0.98684 atm, V₁ = 55 L, T₂ = 30°C = 303.15 K, T₁ = 25°C = 298.15 K, P₂ = 1.03 atm.

As a result, the new volume of the gas is:

V₂ = 0.98684 atm × 55 L × 303.15 K / 298.15 K × 1.03 atm = 53.58 L.

Answer: 53.58 L