Task:
Given a 550 L sample of neon gas that has a temperature of 23 degrees and a pressure of 765 mmHg. Determine how many
moles are present? How many grams is this?
Solution:
According to ideal gas equation: PV = nRT
Pressure = P = 765 mmHg = 1 atm.
Volume = V = 550 L.
Temperature = T = 23°C = (23 + 273.15) = 296.15 K.
Gas constant = R = 0.08206 L*atm*mol-1*K-1.
Then,
n(Ne, g) = PV / RT = (1 atm * 550 L) / (0.08206 L*atm*mol-1*K-1 * 296.15 K) = 22.6318 mol.
n(Ne) = 22.6318 mol.
M(Ne) = 20.1797 g/ mol.
n(Ne) = m(Ne) / M(Ne);
m(Ne) = n(Ne) * M(Ne) = 22.6318 * 20.1797 = 456.703 g
m(Ne) = 456.703 g
Answer: n(Ne) = 22.632 mol; m(Ne) = 456.703 g.
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