Answer to Question #72839 in Chemistry for Brian Mayberry

Question #72839

Calculate the millimoles of solute:
901 mL of a solution containing 5.49 ppm CaCO3

Expert's answer

5.49 ppm means 5.49 mg/L, So 901 ml of the solution contains:
5.49 mg/L ∙ 0.901 L = 4.94649 mg of CaCO3.
ν (CaCO3) = m / M = 4.94649 mg / 100 mg/mmol = 0.0494649 or approx. 0.05 mmol.

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