Question

Given the equation 3H2 + N2 = 2NH3 find how much H2 should be used to produce 170g of NH3

Answer 1

Question #72758, Chemistry / Other / Completed

Given the equation $3\mathrm{H}_2 + \mathrm{N}_2 = 2\mathrm{NH}_3$. Find how much $\mathrm{H}_2$ should be used to produce $170\mathrm{g}$ of $\mathrm{NH}_3$

Solution

$\mathrm{v}(\mathrm{NH}_3) = \mathrm{m}(\mathrm{NH}_3) / \mathrm{M}(\mathrm{NH}_3)$, $\mathrm{M}(\mathrm{NH}_3) = 17\mathrm{g/mol}$, the molar mass.

$\mathrm{v}(\mathrm{NH}_3) = 170\mathrm{g} / 17\mathrm{g} = 10\mathrm{mol}$

Each 3 mol of $\mathrm{H}_2$ produce 2 mole of $\mathrm{NH}_3$. So $\mathrm{v}(\mathrm{H}_2) = 15\mathrm{mol}$.

$\mathrm{V}(\mathrm{H}_2) = \mathrm{v} \cdot \mathrm{Vm} = 15\mathrm{mol} \cdot 22.4\mathrm{L/mol} = 336\mathrm{L}$.

Answer

15 mol or 336 L of $\mathrm{H}_2$.

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