#72737 Chemistry, Other
If the mole fraction of glucose in water is 0.050 for a particular solution, what is the molality of this solution?
A] 5.6 m
B] None of the listed answers are correct
C] 0.50 m
D] 0.34 m
E] 2.9 m
Answer:
(XA x 1000)/ (XB x mol.wt. of B) = molality ‘m’
XB = 1 - XA
XB = mole fraction of water
(XA x 1000)/ (1 - XA) mol.wt. of B = molality ‘m’
XA = mole fraction of glucose
XA = 0.050
1 - XA = 1 - 0.05 = 0.95
m = 0.05 x 1000 / (0.95 x 18)
m = 2.92 mole/kg
Correct answer: E] 2.9 m.
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