Answer to Question #329694 in Chemistry for rae

Question

NiCl3 is a strong electrolyte.

Determine the concentration of each of the individual ions in a 0.550 M NiCl3

0.550 M NiCl3 solution.

Answer 1

Solution:

NiCl₃ is a strong electrolyte that completely dissociates into nickel (Ni³⁺) and chloride (Cl⁻) ions.

The dissociation equation for NiCl₃ in aqueous solution is:

NiCl₃ → Ni³⁺ + 3Cl⁻

From the reaction, one nickel ion and 3 chloride ions are formed.

So, the molarity of nickel ion is same as the molarity of NiCl₃ (0.550 M) and molarity of chloride ions is three times the molarity of NiCl₃, 3×0.550 M = 1.650 M

Thus, the concentration of indiviuatl ions are:

[Ni³⁺] = 0.550 M

[Cl⁻] = 1.650 M

Answer:

Nickel ion (Ni³⁺) concentration is 0.550 M

Chloride ion (Cl⁻) concentration is 1.650 M