Calculate the chloride ion (Cl−)
(Cl−) concentration for a 0.183 M AlCl3
0.183 M AlCl3 solution.
Solution:
AlCl3 → Al3+ + 3Cl−
According to stoichiometry:
Chloride ion (Cl−) concentration = 3 × Molarity of AlCl3
Chloride ion (Cl−) concentration = 3 × 0.183 M = 0.549 M
Answer: The chloride ion (Cl−) concentration is 0.549 M
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