Answer to Question #329690 in Chemistry for rae

Question

How many moles of NaOH

NaOH are present in 26.0 mL

26.0 mL of 0.210 M NaOH

Answer 1

Solution:

Molarity of NaOH solution = Moles of NaOH / Volume of solution

Therefore,

Moles of NaOH = Molarity of NaOH solution × Volume of solution

Moles of NaOH = (0.210 M) × (26.0 mL) × (1 L / 1000 mL) = 0.00546 mol

Moles of NaOH = 0.00546 mol

Answer: 0.00546 moles of NaOH