Answer to Question #320158 in Chemistry for yenyen

Question

how many grams of N2 and H2 is needed to produce 10.0 g NH3?

use the following molar masses:

N2=28g/mol, NH3=17g/mol and H2=2g/mol

Answer 1

Solution:

Balanced chemical equation:

N₂ + 3H₂ → 2NH₃

According to stoichiometry:

1 mol of N₂ produces 2 mol of NH₃

3 mol of H₂ produces 2 mol of NH₃

Thus:

(10.0 g NH₃) × (1 mol NH₃ / 17 g NH₃) × (1 mol N₂ / 2 mol NH₃) × (28 g N₂ / 1 mol N₂) = 8.24 g N₂

Mass of N₂ = 8.24 g

(10.0 g NH₃) × (1 mol NH₃ / 17 g NH₃) × (3 mol H₂ / 2 mol NH₃) × (2 g H₂ / 1 mol H₂) = 1.76 g H₂

Mass of H₂ = 1.76 g

Answer: Requires 8.24 grams of N₂ and 1.76 grams of H₂